C-11-Q037mediumsingle_mcqa+ba−b=c+dc−d\dfrac{a+b}{a-b}=\dfrac{c+d}{c-d}a−ba+b=c−dc+d থেকে যোজন-বিয়োজন বিপরীত প্রয়োগে —aab=cd\dfrac{a}{b} = \dfrac{c}{d}ba=dcbab=dc\dfrac{a}{b} = \dfrac{d}{c}ba=cdca=c,b=da = c, b = da=c,b=ddab=cdab = cdab=cd