C-08-Q139mediumsingle_mcq0<θ<2π0 < \theta < 2\pi0<θ<2π এ sin2θ−cos2θ=cosθ\sin^2\theta - \cos^2\theta = \cos\thetasin2θ−cos2θ=cosθ সমীকরণের সমাধানসমূহ কোনটি?aπ3, π, 5π3\dfrac{\pi}{3},\ \pi,\ \dfrac{5\pi}{3}3π, π, 35πbπ6, π, 11π6\dfrac{\pi}{6},\ \pi,\ \dfrac{11\pi}{6}6π, π, 611πcπ4, π, 7π4\dfrac{\pi}{4},\ \pi,\ \dfrac{7\pi}{4}4π, π, 47πdπ, 2π3, 4π3\pi,\ \dfrac{2\pi}{3},\ \dfrac{4\pi}{3}π, 32π, 34π