C-03-Q163mediumsingle_mcq
In the first full-adder block when adding two numbers, why is CIN1 = 0?
In the first full-adder block when adding two numbers, why is CIN1 = 0?
- aIt is always reset
- bNo carry can come from a previous step when adding the first two bits
- cThe circuit ignores it
- dIt is the sign bit